NDS CW is crypted, trying to decrypt unique pairing mode 0x8B (CAID 0987)

[emmiko]

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yes

 

[DarkStarXxX]

Yes, no Chance.

 

[emmiko]

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:coldsweat:

 

[Alex2018]

too big address space, It will take much more time to find than you alive.

 

[clemenss]

Because:

DES -> 56 bit -> few days
3DES -> 112 bit -> few days x 2^56 = a few trillion days

There are so much more possibilities that a bruteforce is not feasable with current hardware.

 

[jordansv]

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Try it this way.
ins7E "0000000000010202030000000000" (6E736B202F47AC57XXXXXXXX0000000000010202030000000000 )
And show Tag55_01 =???

 

[sasika]

[QUOTE = "jordansv, post: 3761316, member: 329460"]
Try it this way.
ins7E "0000000000010202030000000000" (6E736B202F47AC57XXXXXXXX0000000000010202030000000000)
And show Tag55_01 = ???
[/ QUOTE]

I change that like as you told and now day 55_01_0B

• 2020/03/24 09:04:56 382E2974 r (reader) D8 7B EE 0D 91 23 92 55 00 00 03 23 03 01 22 02
• 2020/03/24 09:04:56 382E2974 r (reader) 00 80 0E 02 03 00 0F 06 00 00 00 00 00 00 20 04
• 2020/03/24 09:04:56 382E2974 r (reader) 00 00 00 00 25 11 00 00 00 00 00 00 00 00 00 00 00
• 2020/03/24 09:04:56 382E2974 r (reader) 00 00 00 00 00 00 00 2A 04 03 23 00 00 55 01 0B
• 2020/03/24 09:04:56 382E2974 r (reader) 56 08 00 00 00 00 00 00 00 00 45 03 40 00 80 2B

Any idea?

Thanks

also after restart oscam it's look line

• D2H_NDS [videoguard2] Decrypted payload
• 2020/03/24 10:23:57 05C171CB r (reader) 00 00 00 00 00 00 00 00 00 00 03 23 03 00 22 02
• 2020/03/24 10:23:57 05C171CB r (reader) 00 80 0E 02 00 00 0F 06 00 10 00 00 00 00 20 04
• 2020/03/24 10:23:57 05C171CB r (reader) 00 00 00 00 25 11 00 00 00 00 00 00 00 00 00 00
• 2020/03/24 10:23:57 05C171CB r (reader) 00 00 00 00 00 00 00 2A 04 03 23 00 00 55 01 88
• 2020/03/24 10:23:57 05C171CB r (reader) 56 08 00 00 00 00 00 00 00 00 45 03 40 00 80 2B
• 2020/03/24 10:23:57 05C171CB r (reader) 02 00 00

 

[clemenss]

I don't know what you are all trying...
It does not matter which mode the card is in (All those mode numbers we don't know what they mean only Cisco knows), as long as you get an ECW.
In the last payload (x88) there is no ECW, in the other (x8B) there is one.

If you have an ECW, the question is how is this ECW encrypted.
If 3DES (or AES or whatever not bruteforceable standard anno 2020) -> no possibilities
If DES -> Possible, if you are able to get a DCW somewhere from (you could also bruteforce it for a given stream, especially if 48 bit CWs are used, for 64bit CWs it's hard)

But my guess is: it's 3DES so just give up.
If you are able to get a DCW somehow try tro bruteforce the ECW/DCW...if not it's very likely 3DES.

 

[sasika]

6E736B202F47AC571xxxxxxxx8CB7D8600010202030000000000

also i put like this and same

• D2H_NDS [videoguard2] Decrypted payload
• 2020/03/24 10:32:36 05C171CB r (reader) 58 6F 96 F6 79 60 19 19 00 00 03 23 03 01 22 02
• 2020/03/24 10:32:36 05C171CB r (reader) 00 80 0E 02 03 00 0F 06 00 00 00 00 00 00 20 04
• 2020/03/24 10:32:36 05C171CB r (reader) 00 00 00 00 25 11 00 00 00 00 00 00 00 00 00 00
• 2020/03/24 10:32:36 05C171CB r (reader) 00 00 00 00 00 00 00 2A 04 03 23 00 00 55 01 8B
• 2020/03/24 10:32:36 05C171CB r (reader) 56 08 00 00 00 00 00 00 00 00 45 03 40 00 80 2B
• 2020/03/24 10:32:36 05C171CB r (reader) 02 00 00

Thanks for your explain

 

[jordansv]

7E is not correct for this card...

 

[Ghafar]

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[fun7]

We write all about german providers here and not about indian. Nobody here from germany
a) knows your provider
b) can give you dcw
c) can give you your unqiue key

 

[Ghafar]

[QUOTE = "fun7, post: 3762688, member: 560877"]
We write all about german providers here and not about indian. Nobody here from germany
a) knows your provider
b) can give you dcw
c) can give you your unique key

Sir Thank u For Repley
Sir please guid me how can i get unique key

 

[Betatester_2000]

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@Ghafar : You've already gotten the correct answer. There is no way possible to bruteforce or calculate your unique Key.

 

[vladtimmy]

[videoguard2] classD3 ins54: Tag55_01 = 8B, ONLY 3DES PARING K1=K2 K3